If | 2x + 3 | + (x-3y + 4) & # 178; = 0, find the value of (Y-1) & # 178; + X # 178

If | 2x + 3 | + (x-3y + 4) & # 178; = 0, find the value of (Y-1) & # 178; + X # 178

2x+3=0
x-3y+4=0
x=-3/2
y=5/6
(y-1)²+x²
=1/36+9/4
=1/36+81/36
=82/36
=41/18
If you have any mistakes, please correct them,