Solving the system of linear equations with three variables {2x-3y = - 16 y-3z = - 2 3x + Z = - 4}

Solving the system of linear equations with three variables {2x-3y = - 16 y-3z = - 2 3x + Z = - 4}

From Formula 3: 3x + Z = - 4, we get: z = - 4-3x, substitute z = - 4-3x into formula 2: y-3z = - 2, we get: y = - 2 + 3Z, that is: y = - 2 + 3Z = - 2 + 3 (- 4-3x) = - 2-12-9x = - 14-9x, then substitute y = - 14-9x into Formula 1: 2x-3y = - 16, we get: 2x-3 (- 14-9x) = - 162x-3 * (- 14) - 3 * (- 9x) = - 162x + 42 + 27x = - 1629x = - 16-4