Let a and B satisfy a3b + ab3-2a2b + 2ab2 = 7ab-8, then A2-B2 = () A. 1b. 3C. 5D. Not sure

∵a3b+ab3-2a2b+2ab2=7ab-8，⇒ab（a2+b2）-2ab（a-b）=7ab-8，⇒ab（a2-2ab+b2）-2ab（a-b）+2a2b2-7ab+8=0，⇒ab（a-b）2-2ab（a-b）+2a2b2-7ab+8=0，⇒ab[（a-b）2-2（a-b）+1]+2（a2b2-4ab+4）=0，⇒ab（a-b-1）...

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