If the value of (2x2 + ax-y + 6) - 2 (bx2-3x + 5y-1) has nothing to do with the value of X, find the value of - 3 (A2 + 2ab-b2) - (4a2-5ab + B2)

If the value of (2x2 + ax-y + 6) - 2 (bx2-3x + 5y-1) has nothing to do with the value of X, find the value of - 3 (A2 + 2ab-b2) - (4a2-5ab + B2)

(2x2 + ax-y + 6) - 2 (bx2-3x + 5y-1) = 2x & sup2; + ax-y + 6-2bx & sup2; + 6x-10y + 2 = (2-2b) x & sup2; + (a + 6) x-11y + 8, because the value of the algebraic formula is independent of the value of X, then the coefficient of X is 02-2b = 0, a + 6 = 0b = 1, a = - 6-3 (A & sup2; + 2ab-b & sup2;) - (4a & sup2; - 5ab + B & sup2