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(1) Given a = 3, B = 1, find the values of A2 + 2Ab + B2 and (a + b) 2; (2) please take another set of values of a and B and calculate the values of the algebraic expressions A2 + 2Ab + B2 and (a + b) 2. What conclusions can you draw from the calculation results?
(1) When a = 3, B = 1, A2 + 2Ab + B2 = 32 + 2 × 3 × 1 + 12 = 16, (a + b) 2 = (3 + 1) 2 = 16, (2) if a = 1, B = - 3, A2 + 2Ab + B2 = 12 + 2 × 1 × (- 3) + (- 3) 2 = 4, (a + b) 2 = (1-3) 2 = 4, conclusion: (a + b) 2 = A2 + 2Ab + B2
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