② Given that the value of the algebraic formula 2 (x2 + ax-y) - 2 (bx2 + 3x) - 5y-1 has nothing to do with the value of the letter X, we can find the value of 2 (a3-2b2-1) - 3 (a3-2b2-1)
Original formula = 2x2 + 2ax-2y-2bx2-6x-5y-1
=(2-2b)x2+(2a-6)x-7y-1
The value is independent of the value of the letter X
So the coefficient is 0
2-2b=0
2a-6=0
So a = 3
b=1
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