For a two digit number, the number on the one digit is 4 less than the number on the ten digit number, and the sum of squares of the number on the one digit and the number on the ten digit is 4 less than the two digit number

Let X be the number of ten, then the number of one is (x-4). The countable equation is: x2 + (x-4) 2 = 10x + (x-4) - 4. The solution of the equation is X1 = 8, X2 = 1.5 (rounding), ∧ x-4 = 4, ∧ 10x + (x-4) = 84

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