A proof of inequality Given that a, B and C are positive real numbers and ab + BC + Ca = 3, it is proved that a ^ 2 + B ^ 2 + C ^ 3 + 3ABC ≥ 6 That's right!

A proof of inequality Given that a, B and C are positive real numbers and ab + BC + Ca = 3, it is proved that a ^ 2 + B ^ 2 + C ^ 3 + 3ABC ≥ 6 That's right!

For example, take a = 11 / 10, B = 1, C = 19 / 21; then AB + BC + Ca = 3, but a ^ 2 + B ^ 2 + C ^ 3 + 3ABC = 1.21 + 1 + (19 / 21) ^ 3 + 20.9/7 is about 5.937, which is not satisfied with ≥ 6; so the topic must be wrong. The topic should be like this: "given that a, B, C are positive real numbers, and ab + BC + Ca = 3, prove a ^ 3 + B ^ 3 +..."

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