The two right sides of a right triangle are the two roots of the equation x-7x + 12 = 0 What is the radius of the circumcircle of this right triangle

The two right sides of a right triangle are the two roots of the equation x-7x + 12 = 0 What is the radius of the circumcircle of this right triangle

The two right angle sides are the two roots of the square - 7x + 12 = 0 of the equation X
x²-7x+12=0
﹙x-3﹚﹙x-4﹚=0
x1=3,x2=4
Bevel = 5
The radius of circumcircle is equal to 2.5