Given that the lengths of two sides of a right triangle are two of the equations x2-7x + 12 = 0, then the length of the third side is______ ．

∵ x2-7x + 12 = 0, that is, (x-3) (x-4) = 0, ∵ x-3 = 0, x-4 = 0, the solution is, X1 = 3, X2 = 4, that is, the two sides of a right triangle are 3 and 4, when 3 and 4 are two right sides, the third side is 32 + 42 = 5; when 4 is hypotenuse and 3 is right side, the third side is = 42 − 32 = 7

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