Let the equation x 2 + (AX) 2-7x-7ax + 2A + 12 = 0 have two equal roots and find the value of A

Let the equation x 2 + (AX) 2-7x-7ax + 2A + 12 = 0 have two equal roots and find the value of A

The original equation is transformed as (x + ax) 2-7 (x + ax) + 12 = 0, (x + ax-3) (x + ax-4) = 0, x + AX = 3 or x + AX = 4, then x2-3x + a = 0 or x2-4x + a = 0. For x2-3x + A = 0, △ = 9-4a = 0, i.e. a = 94, this equation has two equal real roots; for x2-4x + a = 0, △ = 16-4a = 0, i.e. a = 4, this equation has two equal real roots

Elden Ring Premiere

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