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∵x2-7x+12=0,即(x-3)(x-4)=0,∴x-3=0,x-4=0,解得,x1=3,x2=4,即直角三角形的兩邊是3和4,當3和4是兩直角邊時,第三邊是32+42=5;當4是斜邊,3是直角邊時,第三邊是=42−32=7.故答案為:5或7.
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