已知ab是方程X^2-7x+9=0的兩根且a

已知ab是方程X^2-7x+9=0的兩根且a

a+b=7 ab=9
(√a-√b)/√(ab)
=√[(a-2√(ab)+b)/ab]
=√[(a+b-2√(ab))/ab]
=√[(7-2√(9))/9]
=√[(7-6)/9]
=√[1/9]
=1/3