Finding ab-cb = AC with power 2A = 3, power B = 6, power C (a, B, C are all natural numbers)

Because 2 ^ a = 6 ^ C, 2 ^ a = 2 ^ c * 3 ^ C, 2 ^ c * 2 ^ (A-C) = 2 ^ c * 3 ^ C, 2 ^ (A-C) = 3 ^ C, change the B power of both sides of the equation to 2 ^ (a-C) B = 3 ^ BC, because 2 ^ a = 3 ^ B, change the C power of both sides of the equation to 2 ^ AC = 3 ^ BC, combined with the previous conclusion, we get 2 ^ (A-C) B = 2 ^ AC, so (A-C) B = AC, AB CB = AC

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