We know that the positive number a B C satisfies the power a of 2 is equal to the power B of 3 is equal to the power C of 6

alg2=blg3=clg6
a=clg6/lg2
b=clg6/lg3
ab=clg6/lg2 * clg6/lg3=(clg6)^2/(lg2lg3)
ac+bc=(a+b)c=(clg6/lg2+clg6/lg3)c=c^2 lg6(1/lg2+1/lg3)=(clg6)^2/(lg2lg3)
∴ac+bc=ab

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