Lim x tends to infinity. The numerator is SiNx and the denominator is X
|sinx|
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- 1. Lim molecule e - (1 + x) ^ 1 / x, denominator X Because I can't understand the problem-solving process in the book, I ask if there are other ways to solve the problem
- 2. Lim h tends to 0 (x + H) ^ 3-x ^ 3 / h (i.e. denominator is h and molecule is (x + H) ^ 3) to find the limit, please write down the process,
- 3. Lim molecule is ln (1 + x) and denominator is x =? (x tends to 0) Why is it equal to the 1 / x power of Ln (1 + x), isn't ln (1 + x) multiplied by 1 / x? How is 1 / X exponential
- 4. The denominator of LIM (x → 2) is √ x + √ 2. What is the numerator 1?
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- 7. LIM (x) tends to 0) sin (SiNx) / SiNx
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- 10. When x approaches infinity, does Lim sin (x ^ n) / x ^ n exist? When x approaches infinity, does Lim sin (x ^ n) / x ^ n exist?
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- 12. What does LIM (x → 0) tan3x / X equal?
- 13. lim(x→0)tan3x/sin4x (x → 0) is under Lim
- 14. Why does Lim e ^ 1 / (x-1) x tend to be 1 left (1-0) = 0 instead of equal to + infinity
- 15. Why is LIM (x - > infinity) (1-2 / x) ^ (- 1) equal to 1
- 16. Calculate LIM (n →∞) ∑ upper n lower k = 1 (K + 2) / [K! + (K + 1)! + (K + 2)!]
- 17. Find Lim n → + ∞ (1 / N ^ k + 2 / N ^ k + + n / N ^ k) There are three situations,
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- 19. The detailed process of finding LIM (n →∞) ∑ (k = 1, n) K / (n ^ 2 + N + k) limit
- 20. LIM (n →∞) (n ^ 2 + 2) / N + kn = 0 for K