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Lim molecule e - (1 + x) ^ 1 / x, denominator X Because I can't understand the problem-solving process in the book, I ask if there are other ways to solve the problem
1. The molecular limit is equal to E-E and the denominator limit is equal to 0
RELATED INFORMATIONS
- 1. Lim h tends to 0 (x + H) ^ 3-x ^ 3 / h (i.e. denominator is h and molecule is (x + H) ^ 3) to find the limit, please write down the process,
- 2. Lim molecule is ln (1 + x) and denominator is x =? (x tends to 0) Why is it equal to the 1 / x power of Ln (1 + x), isn't ln (1 + x) multiplied by 1 / x? How is 1 / X exponential
- 3. The denominator of LIM (x → 2) is √ x + √ 2. What is the numerator 1?
- 4. (x->0)lim(x * sin1/x) = ? Is that zero or one? Personally, I worked out one. I'm based on the fact that when X - > 0, SiN x is equivalent to X. So I figured it out to be one.
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- 8. LIM (n tends to positive infinity) (1 / 5) ＾ n is equal to what? How to consider or calculate in detail
- 9. When x approaches infinity, does Lim sin (x ^ n) / x ^ n exist? When x approaches infinity, does Lim sin (x ^ n) / x ^ n exist?
- 10. What is the SiNx / X limit when x tends to zero and infinity? Y '= cosx / 1, is the cosx limit 0 or 1?
- 11. Lim x tends to infinity. The numerator is SiNx and the denominator is X
- 12. lim(x-0) tan3x/x=
- 13. What does LIM (x → 0) tan3x / X equal?
- 14. lim(x→0)tan3x/sin4x (x → 0) is under Lim
- 15. Why does Lim e ^ 1 / (x-1) x tend to be 1 left (1-0) = 0 instead of equal to + infinity
- 16. Why is LIM (x - > infinity) (1-2 / x) ^ (- 1) equal to 1
- 17. Calculate LIM (n →∞) ∑ upper n lower k = 1 (K + 2) / [K! + (K + 1)! + (K + 2)!]
- 18. Find Lim n → + ∞ (1 / N ^ k + 2 / N ^ k + + n / N ^ k) There are three situations,
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- 20. The detailed process of finding LIM (n →∞) ∑ (k = 1, n) K / (n ^ 2 + N + k) limit