What is the SiNx / X limit when x tends to zero and infinity? Y '= cosx / 1, is the cosx limit 0 or 1?

lim(x→0)sinx/x=1
This is one of the two important limits. It belongs to 0 / 0 type limit and can also be obtained by using the law of lobita
lim(x→0)sinx/x=lim(x→0)cosx/1=1/1=1
lim(x->∞) sinx/x = 0
Molecular | SiNx|

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