Lim molecule is ln (1 + x) and denominator is x =? (x tends to 0) Why is it equal to the 1 / x power of Ln (1 + x), isn't ln (1 + x) multiplied by 1 / x? How is 1 / X exponential

If x = 0 is brought in, it is found that the numerator and denominator are all zero. This structure is based on the law of lobita, that is, the numerator and denominator are used to calculate the derivative and then the limit respectively
The derivative of Ln (1 + x) is 1 / (1 + x). If x = 0, it is equal to 1. The reciprocal of X is 1
So Lim ln (1 + x) / x = 1

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