The detailed process of finding LIM (n →∞) ∑ (k = 1, n) K / (n ^ 2 + N + k) limit

Because k = 1,
The denominator n ^ 2 + N + k = (n + 1 / 2) ^ 2 + 3 / 4, when (n →∞) the denominator is near infinity,
And because the molecule is 1,
So the formula turns into
lim(x→∞)∑(x) 1/x
The answer is 0

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