lim (x^2sin1/x) /sinx
When x tends to 0, the limit is 0lim (x ^ 2sin1 / x) / SiNx = Lim [(sin1 / x) / (1 / x)] * x / SiNx = Lim [(sin1 / x) / (1 / x)] = 0
Go to infinity without limit
RELATED INFORMATIONS
- 1. LIM (x → 0) (tanx-x) / X3 is the answer 0? PS please see clearly that the molecule is tanx-x, not TaNx SiNx in common questions My own way is: the original formula = LIM (x → 0) (tanx-x) / tanx3 =LIM (x → 0) ((1 / TaNx Square) - X / tanx3 Square) =LIM (x → 0) (1 / xsquare - X / x3) = 0 I don't know if it's right,
- 2. How to do LIM ((TaNx SiNx) / x ^ 3) x - > 0
- 3. Lim e ^ x-e ^ SiNx / Tan ^ 2xln (1 + 2x) (x tends to 0)
- 4. Xsin1 / x + B, x0? )What are the values of a and B, f (x) has a limit at x = 0? (2) what are the values of a and B, f (x) is continuous at x = 0? & nbsp; the more detailed the steps, the better
- 5. If f (x) = {xsin1 / x + B x > o a x = 0.5 + x ^ 2 x
- 6. How to take the values on both sides of the pinch theorem of higher numbers?
- 7. This is a senior number problem in freshman year. We use the pinch theorem to find the limit
- 8. A high number problem, the use of the pinch criterion LIM (1 + 2 ^ n + 3 ^ n) ^ (1 / N) where n tends to infinity, why is its size between 3 and 3 times 3 ^ (1 / N)
- 9. Such as the title, with the pinch theorem! Please prove LIM (x → 0) Tan (x) / x = 1 with pinch theorem
- 10. The pinch theorem proves that the limit of a ^ n / N! Is zero Please prove that a ^ n / N! When n - > + ∞, the limit is zero
- 11. When x tends to zero, five times SiNx, one-third equals zero
- 12. Find Lim [x ^ (n + 1) - (n + 1) x + n] / (x-1) ^ 2 x -- > 1
- 13. lim(x+x^2+…… +x^n-n)/(x-1)
- 14. Find the limit of (TaNx / x) ^ (1 / x ^ 2) when x tends to 0 Using the law of Robida, the answer is e ^ 1 / 3,
- 15. Why is the limit of X / TaNx approaching 0 equal to 1? RT, please write the steps in detail,
- 16. ∫ (3 + (arc TaNx power of 10)) / (1 + (2 power of x)) DX, find its indefinite integral! Most important!
- 17. Indefinite integral of the square of (x times the x power of E) / (x + 1)
- 18. Finding the fourth power of X of indefinite integral e: e ^ x ^ 4
- 19. Lim [[√ (x + 2) (x + 1)] - x] x approaches infinity. How to calculate this problem? The answer is 1 / 2
- 20. LIM (1 + KX) ^ (1 / x) = 2. X - > 0