How to take the values on both sides of the pinch theorem of higher numbers?
Simplify the one to be clamped, and observe that one on both sides of the molecule is taken as 1, and the other is taken as n
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- 1. This is a senior number problem in freshman year. We use the pinch theorem to find the limit
- 2. A high number problem, the use of the pinch criterion LIM (1 + 2 ^ n + 3 ^ n) ^ (1 / N) where n tends to infinity, why is its size between 3 and 3 times 3 ^ (1 / N)
- 3. Such as the title, with the pinch theorem! Please prove LIM (x → 0) Tan (x) / x = 1 with pinch theorem
- 4. The pinch theorem proves that the limit of a ^ n / N! Is zero Please prove that a ^ n / N! When n - > + ∞, the limit is zero
- 5. Using pinch theorem to find limit Find the limit of LIM (2x [3 / x], X tending to 0, where [x / 3] represents the integer function of 3 / X
- 6. The pinch theorem is used to find the limit, Xn=(A1^n+A2^n+…… +AK ^ n) to the power of N, where a1 > A2 > >Ak>0
- 7. lim(x→0)lncos2x/lncos3x Using equivalent infinitesimal to calculate
- 8. When x → 0, Lim {lncos2x / lncos3x} = Lim {(lncos2x) '/ (lncos3x)'} = Lim {2tan2x / 3tan3x} The specific steps of (lncos2x) '= 2tan2x
- 9. LIM (x tends to 0) ((e ^ x) * sinx-x (1 + x)) / x ^ 3 is solved by Taylor's theorem
- 10. Using Taylor formula to find the limit of [cosxln (1 + x) - x] / x ^ 2 and [e ^ x-x (1 + x)] / (x ^ 2 * SiNx)
- 11. If f (x) = {xsin1 / x + B x > o a x = 0.5 + x ^ 2 x
- 12. Xsin1 / x + B, x0? )What are the values of a and B, f (x) has a limit at x = 0? (2) what are the values of a and B, f (x) is continuous at x = 0? & nbsp; the more detailed the steps, the better
- 13. Lim e ^ x-e ^ SiNx / Tan ^ 2xln (1 + 2x) (x tends to 0)
- 14. How to do LIM ((TaNx SiNx) / x ^ 3) x - > 0
- 15. LIM (x → 0) (tanx-x) / X3 is the answer 0? PS please see clearly that the molecule is tanx-x, not TaNx SiNx in common questions My own way is: the original formula = LIM (x → 0) (tanx-x) / tanx3 =LIM (x → 0) ((1 / TaNx Square) - X / tanx3 Square) =LIM (x → 0) (1 / xsquare - X / x3) = 0 I don't know if it's right,
- 16. lim (x^2sin1/x) /sinx
- 17. When x tends to zero, five times SiNx, one-third equals zero
- 18. Find Lim [x ^ (n + 1) - (n + 1) x + n] / (x-1) ^ 2 x -- > 1
- 19. lim(x+x^2+…… +x^n-n)/(x-1)
- 20. Find the limit of (TaNx / x) ^ (1 / x ^ 2) when x tends to 0 Using the law of Robida, the answer is e ^ 1 / 3,