Such as the title, with the pinch theorem! Please prove LIM (x → 0) Tan (x) / x = 1 with pinch theorem

The upper limit, TaNx = SiNx / cosx, so LIM (x → 0) Tan (x) / x = LIM (x → 0) SiNx / (cosx * x) because SiNx is less than x, so LIM (x → 0) Tan (x) / X LIM (x → 0) 1 / cosx = 1
The lower limit, because TaNx ″ x, LIM (x → 0) Tan (x) / X ″ X / x = 1
(the problem should be LIM (x → 0), on SiNx "x constructable function y = sinx-x is proved, similarly, TaNx" x is proved.)

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