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LIM (x → 0) (tanx-x) / X3 is the answer 0? PS please see clearly that the molecule is tanx-x, not TaNx SiNx in common questions My own way is: the original formula = LIM (x → 0) (tanx-x) / tanx3 =LIM (x → 0) ((1 / TaNx Square) - X / tanx3 Square) =LIM (x → 0) (1 / xsquare - X / x3) = 0 I don't know if it's right,
Let's use the law of Robita: Lim [(secx) ^ 2 - 1] / (3x ^ 2) or 0 / 0 limit, continue to use the law of Robita = Lim [2secx * (secx * TaNx)] / (6x) = Lim [(secx) ^ 2 * TaNx] / (3x) or 0 / 0 limit, continue to use the law of Robita = Lim [2secx * (secx * TaNx) * TaNx
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