Special solution of differential equation y '= y satisfying initial condition y (0) = 1 Right away

The general formula of Y '= y
dy/dx=y
1/y dy=dx
y=Cexp(x)
And Y (0) = 1
1=Cexp(0)
C=1
So,
The solution of the initial condition y (0) = 1 is y '= y
y=exp(x)

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