Contact us
Choose a category below so we can get back to you as quickly as possible.
y'=y的通 dy/dx=y 1/y dy=dx y=Cexp(x) 又y(0)=1 1=Cexp(0) C=1 所以, y'=y初始條件y(0)=1的解是: y=exp(x)
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.