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方程的齊次形式: y''-2y'+y=0 特徵方程為: λ^2-2λ+1=0 λ=1(重根) 又:Q=x^2*e^x 1是特徵方程的重根, 所以,設方程的一個特解為: y*=x^2(Ax^2+Bx+c)*e^x帶入方程,解出A、B、C 原方程解為: y=Ce^x+y*
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