Contact us
Choose a category below so we can get back to you as quickly as possible.
設特解y*=ax²;+bx+c,則y*'=2ax+b,y*“=2a,代入原方程,得2a+2(2ax+b)+(ax²;+bx+c)=x²;+1,即ax²;+(4a+b)x+(2a+2b+c)=x²;+1.得a=1,b=-4,c=7故特解y*=x²;-4x+7
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.