Contact us
Choose a category below so we can get back to you as quickly as possible.
令y*=ax²;+bx+c則y*'=2ax+b,y*“=2a,代入原方程,2a+2(2ax+b)+ax²;+bx+c=3 即有ax²;+(4a+b)x+(2a+2b+c)=3,則a=0,b=0.c=3 故y*=3
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.