The second derivative of y to x equals ax & sup3; + B I know that first let the first derivative of y be equal to u, and then change it into the first derivative of u by substitution, but then a polynomial with the square of u equal to x appeared, and I can't do it any more Seek expert solution Wrong, it's equal to ay & sup3; + B Otherwise it would be too simple~

What? Y "= ax ^ 3 + B
It only contains x, so the direct integral is not it?
y'=(a/4)x^4+bx+C1
y=(a/20)x^5+(b/2)x^2+C1x+C2

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