Finding the special solution of differential equation y '- y = cosx, x = 0, y = 0
Constant variation method: when solving the first-order non-homogeneous linear differential equation dy / DX + P (x) y = q (x) [Q (x) ≠ 0], the first-order homogeneous linear differential equation y = CE ^ (- ∫ P (x) DX is solved with Q (x) = 0, then the C in the general solution is changed to u (x), and then the transformed general solution is brought into the original equation to solve U (x)
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- 1. The solution y =? Of the differential equation y '' + 2Y '+ y = 0?
- 2. Finding the special solution of differential equation y '- 2Y / (1-x ^ 2) = x + 1, x = 0, y = 0
- 3. Find the special solution of y = y '= 0 when y' '+ (y)' ^ 2 = 1 and x = 0
- 4. 1. A straight line is cut by two straight lines L1: 4x + y + 6 = 0, L2: 3x-5y-6 = 0, and the midpoint of the line segment is P point. When the coordinate of P point is (0,0), find the straight line 1. A straight line is cut by two straight lines L1: 4x + y + 6 = 0, L2: 3x-5y-6 = 0, and the midpoint of the line segment is P point. When the coordinate of P point is (0,0), the linear equation is solved 2. If the line L and two lines y = 1, x-y-7 = 0 intersect at P and Q respectively, the middle point of the line PQ is (1, - 1) the equation for solving L
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- 7. Finding tangent and normal plane equation of curve y ^ 2 = 2mx Z ^ 2 = M-X at point (x.y.z.)
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- 11. Differential equation solution: y '- ysinx - y ^ 2 + cosx = 0
- 12. Solve the differential equation (x ^ 2-1) y '+ 2XY cosx = 0, thank you very much! (x ^ 2-1) y & # 39; + 2XY cosx = 0, the garbled part is the derivative of Y, detailed process
- 13. Which differential equation is y = cosx
- 14. Solving differential equation y '= cosx / Y
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- 16. Does the content of the third postgraduate entrance examination of mathematics include the higher order differential equation that can reduce the price
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- 19. The second derivative of y to x equals ax & sup3; + B I know that first let the first derivative of y be equal to u, and then change it into the first derivative of u by substitution, but then a polynomial with the square of u equal to x appeared, and I can't do it any more Seek expert solution Wrong, it's equal to ay & sup3; + B Otherwise it would be too simple~
- 20. The reducible higher order differential equation XY '+ 1 = y' ^ 2