On the problem of solving second order non homogeneous linear differential equation with constant coefficient in postgraduate entrance examination mathematics It is known that the equation is a second-order non-homogeneous linear differential equation with constant coefficients, and it has two special solutions: Y1 = cos2x-1 / 4xsin2x, y2 = sin2x-1 / 4xsin2x. Now the expression of the equation is required. Let the general solution of the equation be y = C1 * cos2x + C2 * sin2x - 1 / 4sin2x, where C1 and C2 are arbitrary constants, Cos2x and sin2x should be a special solution of the corresponding homogeneous differential equation, - 1 / 4sin2x should be a special solution of this equation, but the problem does not give these two conditions, ah, hope to have a great God to help solve, thank you! | Math enthusiast | Mathematical art

On the problem of solving second order non homogeneous linear differential equation with constant coefficient in postgraduate entrance examination mathematics It is known that the equation is a second-order non-homogeneous linear differential equation with constant coefficients, and it has two special solutions: Y1 = cos2x-1 / 4xsin2x, y2 = sin2x-1 / 4xsin2x. Now the expression of the equation is required. Let the general solution of the equation be y = C1 * cos2x + C2 * sin2x - 1 / 4sin2x, where C1 and C2 are arbitrary constants, Cos2x and sin2x should be a special solution of the corresponding homogeneous differential equation, - 1 / 4sin2x should be a special solution of this equation, but the problem does not give these two conditions, ah, hope to have a great God to help solve, thank you!

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