Differential equation solution: y '- ysinx - y ^ 2 + cosx = 0 | Math enthusiast | Mathematical art

Differential equation solution: y '- ysinx - y ^ 2 + cosx = 0

The original equation is reduced to (y + SiN x) '= y (y + SiN x), let z = y + sin X,
Z '= Z (z-sin x), that is, Z' + zsin x = Z ^ 2. This is the Bernoulli equation and can be solved

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