If the ordinate of the lowest point of the parabola y = (m-1) x2 + 2mx + 2m-1 is zero, then M=______ ．

According to the meaning of the problem, according to the coordinate formula of the vertex of the function, 4ac-b24a = 4 (m-1) (2m-1) - (2m) 24 (m-1) = 0, the solution is m = 3 ± 52, and the parabola has the lowest point, the opening of the image is upward, ｜ M-1 ＞ 0, that is, m ＞ 1, ｜ M = 3 + 52

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