It is known that the line AB, a (6,0) and point B move on the curve c y = x ^ 2 + 3, and the trajectory equation of point P in AB is obtained

It is known that the line AB, a (6,0) and point B move on the curve c y = x ^ 2 + 3, and the trajectory equation of point P in AB is obtained

Let B coordinate be (XB, XB ^ 2 + 3), p be (x0, Y0)
be
2x0=xb+6
2y0=xb^2+3
We can get XB = 2x0-6 by substituting
2y0=39-24 x0+4x0^2
It is reduced to Y0 = 2x0 ^ 2-12x0 + 39 / 2
So the trajectory equation of P is y = 2x ^ 2-12x + 39 / 2