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根據題意,根據函數的頂點的座標公式得,4ac-b24a=4(m-1)(2m-1)-(2m)24(m-1)=0,解得m=3±52,又抛物線有最低點,圖像開口向上,∴m-1>0,即m>1,∴m=3+52.
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