If the solution set of the inequality MX + 4 ＜ 2x + 2m of X is x ＞ 2, then the value range of M is______ ．

If the solution set of the inequality MX + 4 ＜ 2x + 2m of X is x ＞ 2, then the value range of M is______ ．

The original inequality can be reduced to: (m-2) x ＜ 2 (m-2), ∵ the solution set of inequality MX + 4 ＜ 2x + 2m is x ＞ 2, ∵ m-2 ＜ 0, the solution is m ＜ 2. So the answer is: m ＜ 2

What is the density of steel or iron?

The density of steel is 7.85g/cm3
Grey cast iron 6.7.4
White cast iron 7.7.72
Malleable cast iron 7.7.43
Cast steel 7.8
Industrial pure iron 7.8759

There are two bags of cement in the construction site, a total of 600 bags. If 25 bags are taken from pile a and put into pile B, then the remaining bags in pile a are four times as many as those in pile B, and the two piles of cement are different
How many bags are there?

B now has: 600 (1 + 4) = 120 Bags
A now has: 120 × 4 = 480 bags
B: 120-25 = 95 bags
A: 480 + 25 = 505 bags

A cylindrical steel block, the bottom radius and height are 6 decimeters, melt it into a cone of equal height, how many square decimeters is the bottom area of the cone?

What is the volume of the steel block
6 × 6 × 3.14 × 6 = 678.24 (cubic decimeter)
What is the base area of the cone
678.24 × 3 △ 6 = 339.12 (square decimeter)

A number is a factor of 36 and a multiple of 9. This number may be______ ．

Because the multiples of 9 are 9, 18, 27, 36 The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36; so this number may be: 9, 18, 36; so the answer is: 9, 18, 36

Under the decomposition factor: x4-2x2-8 x2-3xy + 2y22x2-7x + 3 x2 + 2x-15-ax-5a, the solution equation is: 1999x2-2000x + 1 = 0 x2-14x + 13 = 0
1949X2-1999X+50=0

Under factorization factor: x4-2x2-8 = (X & # 178; - 4) (X & # 178; + 2) = (x + 2) (X-2) (X & # 178; + 2) x2-3xy + 2Y2 = (x-2y) (X-Y) 2x2-7x + 3 = (2x-1) (x-3) x2 + 2x-15-ax-5a = (x + 5) (x-3) - A (x + 5) = (x + 5) (x-3-a) solution equation: 1999x2-2000x + 1 = 0 (1999x-1) (x-1) = 0x = 1 / 1999

Two times of a number is more than half of his 4.56 how to do?

Let this number be X
2x-1/2x=4.56
3/2x=4.56
x=3.04
A: the number is 3.04

Given that the variables X and y satisfy the constraint conditions X-Y + 2 ≤ 0, X ≥ 1, x + Y-7 ≤ 0, what is the value range of x ^ 2 + y ^ 2

First, we make three straight lines in the plane rectangular coordinate system xoy: X-Y + 2 = 0, x = 1, x + Y-7 = 0
X-Y + 2 ≤ 0 means the line X-Y + 2 = 0 and the area under the line;
X ≥ 1, which means the line x = 1 and the area on the right side of the line;
X + Y - 7 ≤ 0 means the line x + Y - 7 = 0 and the area under the line
Therefore, the region of constraint conditions represents the semi infinite region under the line X-Y + 2 = 0, on the right side of the line x = 1 and under the line x + Y-7 = 0
And x ^ 2 + y ^ 2 represents a circle with the origin o (0,0) as the center and the radius r = √ (x ^ 2 + y ^ 2)
Obviously, the minimum value of x ^ 2 + y ^ 2 is 1 ^ 2 = 1, and the maximum value is ∞, that is, the range is [1, + ∞]

Use a square frame to set 2 × 2 numbers on the calendar. The sum of the four numbers is 76. What are the four numbers?

Let the smallest number be x, then the other three numbers are x + 1, x + 7 and X + 7 + 1 respectively. According to the meaning of the question, we get x + (x + 1) + (x + 7) + (x + 7 + 1) = 76. Solving the equation, we get x = 15, then the other three numbers are 16, 22 and 23. Answer: these four numbers are 15, 16, 22 and 23 respectively

Write out the integer solution of the quadratic equation 3x + 4Y = 11

X=1,Y=2