The perimeter of a circular flower garden is 28.26 meters, in which one fifth of the area is reserved for planting roses. How many square meters is the area of planting roses?

The perimeter of a circular flower garden is 28.26 meters, in which one fifth of the area is reserved for planting roses. How many square meters is the area of planting roses?


Radius 28.26 △ 3.14 △ 2 = 4.5m
Rose area
3.14 × 4.5 × 4.5 × 1 / 5 = 12.717 square meters



The garden has a round flower bed with a circumference of 25.12 meters. 40% of the total area of the flower bed is planted with peony, 1 / 3 of rose, and the rest with rose. The area of planting rose is larger than that of planting month
What percentage more is the area of the season?


1. The percentage of rose species: 1-40% - 1 / 3 = 4 / 15;
2. It should be that the area of rose is ()% less than that of rose
(1 / 3-4 / 15) △ 1 / 3 = 20% or 1-4 / 15 △ 1 / 3 = 20%



How to convert kilowatts into degrees?
For example, how many kilowatts of electricity does an electrical appliance consume per hour?


It was once
Degree, is a kilowatt of electrical power consumed in an hour



How VB calculates the value of a + 2B + 3C + 4D + 5E and displays the formula
In a circular way


Dim s(1 To 5), z As Integer
Dim sStr, zStr As String
Dim i As Integer
sStr = "abcde"
For i = 1 To 5
S (I) = InputBox ("please enter the value of" & mid (STR, I, 1) & amp; "))
If i > 1 Then
zStr = zStr & "+" & s(i) & "*" & i
Else
zStr = s(i)
End If
z = z + s(i) * i
Next i
MsgBox "a+2b+3c+4d+5e=" & zStr & "=" & z



Is the voltage at both ends of the load multiplied by the current passing through the load equal to the actual power of the load


In DC system, the voltage at both ends of the load multiplied by the current passing through the load is equal to the actual power of the load; in AC single-phase load, the voltage at both ends of the load multiplied by the current passing through the load is equal to the apparent power of the load, and then multiplied by the power factor is the actual active power, The voltage at both ends of the load multiplied by the current passing through the load, then multiplied by the root 3 equals the apparent power of the load, and then multiplied by the power factor is the actual active power



A rope is 2 / 3M long. It is divided into 6 sections on average. The length of each section is several meters, and the length of each section accounts for several parts of the total length


2 / 3m / 6 = 1 / 18m, the length of each section accounts for 1 / 6 of the total length



What is the SI unit of time?


Second, s (the first letter of second)



One end of the vertical spring is connected with the horizontal plane with mass m, and the other end is fixed with the ground. Its obstinacy coefficient is K. a mud ball with mass m is placed on the distance plate M
The maximum displacement of the mud ball and the flat plate moving downward together is calculated


The process of mud ball falling: let the final velocity be v 2GH = V & # 178; & nbsp; & nbsp; & nbsp; v = √ 2GH, the process of completely inelastic collision between mud ball and m, the conservation of momentum: let the common velocity after collision be v 1mV = (M + m) V 1V 1 = m √ (2GH) & nbsp; / (M + m), the process of compressing the spring to the lowest point, the conservation of mechanical energy: let the spring original



220v25w, 220v40w and connected in 110V circuit, the brighter lamp is
Why


Of course, it is 40W, with high power and low resistance. Although the voltage is low, the resistance remains the same. The current with small resistance is large, and the current with large power does more work, so it is brighter than 25W. The calculation method calculates the resistance of two bulbs 220 × 220 △ 40 = 1210 Ω, 220 × 220 △ 25 = 1936 Ω according to P = u &



The iron ball with a volume of 5 m3 is immersed in alcohol with a density of 0.8 × 103 kg / m3, and the buoyancy of alcohol is Newton


Your formula for buoyancy is f (buoyancy) = ρ (liquid) GV (row is volume)
Then the numbers are brought in 0.8 × 10 & sup3; × 9.8 × 5
Then calculate the answer = 3.92 × 10 ^ 4N
3.92 ×10^4(N))
ρ=0.8×10³kg/m³ g=9.8N/kg V=5m³
F=ρgv=0.8×10³×9.8×5=3.92×10^4N