Decomposition factor: 1.9 (a-b) ^ 2-16 (a + b) ^ 2.3x ^ 3-12x ^ 2Y + 12xy ^ 2 3.25 (X-Y) ^ 2 + 10 (Y-X) + 1

Decomposition factor: 1.9 (a-b) ^ 2-16 (a + b) ^ 2.3x ^ 3-12x ^ 2Y + 12xy ^ 2 3.25 (X-Y) ^ 2 + 10 (Y-X) + 1

1 9（a-b)^2-16(a+b)^2=-7a^2-50ab-7b^2=-(7a+b)(a+7b)2 3x^3-12x^2y+12xy^2=3x(x^2-4xy+4y^2)=3x(x-2y)^23 25(x-y)^2+10(y-x)+1=25(x-y)^2-10(x-y)+1=[5(x-y)-1]^2=(5x-5y-1)^2

(1) 9（m+n)²-16（m-n）² （2） （x+y)²+10（x+y)+25
(1) 9（m+n)²-16（m-n）² （2） （x+y)²+10（x+y)+25 （3） 4a²b²-（a²+b²）² （4） （c²-a²-b²)²-4a²b² （5）(x+p)²-(x-q)²

(1)
9(m+n)²-16(m-n)²
=[3(m+n)+4(m-n)][3(m+n)-4(m-n)]
=(7m-n)(-m+7n)
(2)
(x+y)²+10(x+y)+25
=(x+y+5)²
(3)
4a²b²-(a²+b²)²
=(2ab)²-(a²+b²)²
=(2ab+a²+b²)(2ab-a²-b²)
=-(a+b)²(a-b)²
(4)
(c²-a²-b²)²-4a²b²
=(c²-a²-b²)²-(2ab)²
=(c²-a²-b²+2ab)(c²-a²-b²-2ab)
=[c²-(a-b)²][c²-(a+b)²]
=(c+a-b)(c-a+b)(c+a+b)(c-a-b)
(5)
(x+p)²-(x-q)²
=(x+p+x-q)(x+p-x+q)
=(p+q)(2x+p-q)
If you don't understand, I wish you a happy study!

The hypotenuse of isosceles right triangle with known waist 40 is calculated and substituted into the formula

C & # 178; = A & # 178; + B & # 178;, a = b = 40, then
c²=40²+40²
c²=3200
c=√3200=40√2

There is a passenger carrying 30kg luggage from Shanghai to Beijing by plane. According to the regulations of CAAC, the passenger can carry 20kg luggage for free at most, and the overweight part can buy the luggage ticket at 1.5% of the air ticket price. Now the passenger has bought the luggage ticket of 180 yuan, how much should the air ticket price be?

Suppose the air ticket price should be x yuan, from the question meaning: (30-20) × 1.5% & nbsp; X = 180, the solution is: x = 1200, answer: the air ticket price should be 1200 yuan

The law of addition, subtraction, multiplication and division of negative and positive numbers

On the horizontal ground, pull the 100N trolley forward 5m with 50N force along the horizontal direction, and the work done by the pulling force is equal to______ J. Work done by gravity______ J．

(1) The work done by pulling force is w = FS = 50N × 5m = 250j; (2) the direction of gravity is vertical and downward, while the object moves 5m horizontally without moving distance in the direction of gravity, so the work done by gravity is 0j

In the sequence {an}, if the first n terms and Sn = 3 + 2An are known, the formula for finding A1, A2, A3, A4 and general terms is obtained
N is the subscript of A. don't make a mistake

(1) When A1 = S1 = 3 + 2a1a1 = - 3s2 = a1 + A2 = 3 + 2a2a2 = a1-3 = - 3-3 = - 6s3 = a1 + A2 + a3 = 3 + 2a3a3 = a1 + a2-3 = - 3-6-3 = - 12s4 = a1 + A2 + a3 + A4 = 3 + 2a4a4 = a1 + A2 + A3-3 = - 3-6-12-3 = - 24 (2) n ≥ 2, an = SN-S (n-1) = 3 + 2An - [3 + 2A (n-1)] an = 2A (n-1) an / a (n-1) = 2

A car is driving along a straight line at a speed of 8 m|s, and suddenly accelerates at an acceleration of 1 m|s * 2

2as=vt^2-v0^2
2*1*18=vt^2-64
Vt = 10 or - 10 (round)
So: final speed VT = 10m / S

The inner perimeter of a runway is 400m, the outer R is 44m, the inner R is 40m, Xiaoming and Xiaogang 400m Race, Xiaoming run R, Xiaogang run R. if the focus is the same, then
How many meters is the starting point of the two

It means to connect two semicircles with a straight line between them
If the end point is the same, it should be in the straight line, that is, the starting point. Then both of them must pass through the perimeter of the whole circle. Therefore, the perimeter difference is π (88-80) = 8 π≈ 25m
And (400-80 π) △ 2 > 25 is in line with the meaning of the question, so the starting point of the two people should be about 25m apart

It is known that one root of the equation x2 + (K-3) x + K2 = 0 is greater than 1, and the other root is less than 1
Finding the value range of real number k
It's the square of X
Explain the specific reasons

On the equation x2 + (K-3) x + K2 = 0 of X, one root is greater than 1 and the other root is less than 1
Measurable (x1-1) * (x2-1)