Factorization x ^ 2 + 15 + 7

Factorization x ^ 2 + 15 + 7

It should be 2x ^ 2 + 15x + 7
Multiplication by cross
2x^2+15x+7
=(2x+1)(x+7)
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(Y-1) ^ = 3 (1-y) factorization, quick solution

(y-1)²=3(1-y)
(y-1)²=-3(y-1)
(y-1)²+3(y-1)=0
(y-1)[(y-1)+3]=0
(y-1)(y+2)=0
y1=1,y2=-2

Factorization of Y ^ 4-5y ^ 2-36

y^4-5y^2-36
=(y^2-9)(y^2+4)
=(y-3)(y+3)(y^2+4)

Factorization x ^ 2-5y ^ 2

x^2-5y^2
=x^2-(√5y)^2
=(x+√5y)(x-√5y)

If the perimeter of a rectangle is 8 cm and the diagonal is 10 cm, the area of the rectangle is

Let the rectangle be a cm in length and B cm in width
Then a ^ 2 + B ^ 2 = 10
So there is
(a+b)^2-2ab=10
Because the circumference of the rectangle is 8 cm
SO 2 (a + b) = 8
We can get a + B = 4
In the previous equation:
4^2-2ab=10
2ab=4^2-10
2ab=16-10
2ab=6
ab=3
That is, the area of this rectangle is 3 square centimeters

If Y-X = - 3, xy = 28, try to find the value of X & # 178; y-xy & # 178

x²y-xy²
=xy(x-y)
=28*3
=84

7 / 2x + 3 / 2x = 1 and 21 / 19

Turn 19 out of 1 and 21 into a false score of 40 out of 21
Multiply both sides by 21 to get 6x + 14x = 40
20X=40
X=2

The straight line m passing through the point m (- 2,0) intersects with the ellipse X22 + y2 = 1 at P1, P2, and the midpoint of the line p1p2 is p. suppose the slope of the straight line m is K1 (K1 ≠ 0), and the slope of the straight line OP is K2, then calculate the value of k1k2

The equation of the straight line m passing through the point m (- 2, 0) is & nbsp; y-0 = K1 (x + 2), and the equation of substituting into the ellipse is reduced to (2k12 + 1) x2 + 8k12x + 8k12-2 = 0, ∧ X1 + x2 = − 8k122k12 + 1, ∧ P's abscissa is − 4k122k12 + 1, ∧ P's ordinate is K1 (x1 + 2) = 2k12k12 + 1, that is point P (− 4k122k12 + 1, 2k12k12 + 1), the slope of the straight line OP is K2 = − 12k1, ∧ k1k2 = - 12

We usually use decimal numbers, but in computer program processing, we only use binary numbers of 0 and 1. These two numbers can be converted to each other. For example, if we convert binary number 1011 to decimal, it should be 1 × 23 + 0 × 22 + 1 × 21 + 1 × 20 = 11. In this way, we convert decimal 6 to binary, it should be 1 × 23 + 0 × 22 + 1 × 21 + 1 × 20 = 11

110..
Well, I majored in it operation and maintenance in the school of information engineering
These numbers are calculated naturally when they are used to it
If 6, the nearest power of 2 is 8
It's binary 1000
Minus two, it's 110
This method is only suitable for small numbers
Large factorization, with 2 short division, and then calculate the remainder, more trouble
I won't say more. Anyway, it's something that I only used in college

Polynomial 2A ^ B-1 / 4B ^ 3-A ^ 3B ^ / 2 + A ^ 4
(1) They are arranged in descending order of A. (2) In descending order of B

（1）2+a^4 4b^3-a^3b^ 2a^b-1
(1) 4b ^ 3-A ^ 3B 2A ^ B-1 in the end, it doesn't matter if there is no B in it