When solving the equations ax + y = 10, x + by = 7, because a carelessly misread a in the equations, the solution is x = 1, y = 6, B misread B in the equations, and the solution is x = - 1, y = 12 1. Find the value of a and B 2. Find out the solution of the original equation

When solving the equations ax + y = 10, x + by = 7, because a carelessly misread a in the equations, the solution is x = 1, y = 6, B misread B in the equations, and the solution is x = - 1, y = 12 1. Find the value of a and B 2. Find out the solution of the original equation

1. If we take x = 1y = 6 into x + by = 7, we get,
1+6b=7,b=1
If x = - 1y = 12 is brought into ax + y = 10,
-a+12=10,a=2
2, the original equation is 2x + y = 10, x +, y = 7,
The solution is x = 3, y = 4

If the system of equations y = x ^ 2 + 2x-3
y=kx
The solutions are x = X1 and x = x2
Y = Y1, y = Y2, and Y1 + y2 = 3, find the value of K

Simultaneous equations y = x & sup2; + 2x-3y = KXX & sup2; + 2x-3 = KXX & sup2; + (2-k) x-3 = 0 because the solutions of the equations are x1, Y1 and X2, Y2, so Y1 + y2 = K (x1 + x2) = 3, so X1 + x2 = 3 / K according to Weida's theorem, X1 + x2 = - (2-k) so - (2-k) = 3 / KK & sup2; - 2k-3 = 0 (K + 1) (K-3)

Find the value of (x + 1) (X & # 178; + 1) (x ^ 4 + 1) (x ^ 8 + 1)... (x ^ 64 + 1)

Original formula = (x-1) (x + 1) (X & # 178; + 1) (x ^ 4 + 1) (x ^ 8 + 1)... (x ^ 64 + 1) / (x-1)
=(x²-1)(x²+1)（x^4+1）(x^8+1)...(x^64+1)/(x-1)
Using the square difference repeatedly
=(x^128-1)/(x-1)

There is an ammeter with resistance Rg of 15000 ohm and full bias current Ig of 80 microampere. To refit it into a 3V voltmeter, how much resistance should be connected in series

The negative sixth power of (1500 x) 80 times 10 = 3V
x=22500

When k is a value, the solution of the equation 34 + 8x = 7K + 6x about X is 6.5 times larger than that of the equation K (2 + x) = x (K + 2) about X

The solution of the equation 34 + 8x = 7K + 6x is: x = 28K − 38; the solution of the equation K (2 + x) = x (K + 2) is: x = k, according to the meaning of the problem, 28K − 38-k = 6, the solution is k = 5120

The resistance of a resistance wire with uniform thickness is 1 ohm. If the resistance wire is uniformly elongated so that the diameter of the elongated resistance wire is one third of the original diameter, the resistance of the elongated resistance wire is (d)
(a) 3 Euro; (b) 9 euro; (c) 27 euro; (d) 81 euro
I figured it out to be 27. I don't know why it's D. I need detailed steps and explanations. Thank you

When the diameter is one third of the original diameter, the area of the resistance wire is one ninth of the original, and the resistance value per unit length is nine times of the original. At this time, the length of the resistance wire is nine times of the original, so the resistance of the extended resistance wire is (d) 81 Ω

Given the inequality f (x) > 1 / X of function f (x) = (X & # 178; - ax + a) / x, X ∈ [1, + ∞) solution about X

(x) (x (x) = (x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\- 1}

What's the power consumption of one watt per hour? Is 100 watt 100?

Hello, what we mean by the power consumption of household appliances is how many watts per hour. 1000 watts per hour. 1 watt = 0.001 kwh / hour. 100 watt = 0.1 kwh / hour. The calculation method is to calculate the specific power (Watts) and calculate the daily power consumption per hour

Who knows the simple calculation method of "7 out of 13 × 1 out of 2 × 39"?

7/13×1/2×39
＝7/13×39×1/2
＝21×1/2
＝21/2
＝10.5

How many yards can electric cars run when they are refitted with 72V + 800W motors~

This question is too general
At least you need to know the capacity of your battery, how many batteries are in series and parallel, so as to calculate the power capacity, and how to design your control circuit, open or conservative, constant voltage or constant current