Decompose the factor and write the result 8A (x-a) + 4B (A-X) - 6C (x-a)=______ ．

Decompose the factor and write the result 8A (x-a) + 4B (A-X) - 6C (x-a)=______ ．

8A (x-a) + 4B (A-X) - 6C (x-a) = 2 (x-a) (4a-2b-3c)

It is known that x ^ 3 + mx-4 can be factorized in the range of integers

X ^ 3 + mx-4 can be factorized in the range of integers. It shows that the equation x ^ 3 + mx-4 = 0 has an integer root, and its integer root must be a factor of 4, so its roots can only be - 4, - 2, - 1, 1, 2, 4
If the root is - 4, substituting it into the equation, we can get m = - 17, then x ^ 3-17x-4 = (x + 4) (x ^ 2-4x-1);
If the root is - 2, substituting it into the equation, we can get m = - 6, then x ^ 3-6x-4 = (x + 2) (x ^ 2-2x-2);
If the root is - 1, substituting it into the equation, we can get m = - 5, then x ^ 3-5x-4 = (x + 1) (x ^ 2-x-4);
If the root is 1, M = 3 can be obtained by substituting it into the equation, then x ^ 3 + 3x-4 = (x-1) (x ^ 2 + X + 4);
If the root is 2, substituting it into the equation, we can get m = - 2, then x ^ 3-2x-4 = (X-2) (x ^ 2 + 2x + 2);
If the root is 4, substituting it into the equation, we can get m = - 15, then x ^ 3-15x-4 = (x-4) (x ^ 2 + 4x + 1)

x. Y is a natural number, and X (x-u) - Y (Y-X) + 12, find the value of x.y
fast
one
And X (X-Y) - Y (Y-X) = 12

x(x-y)-y(y-x)=12
x(x-y)+y(x-y)=12
(x-y)(x+y)=12
x^-y^=12
x=4;y=2

Given the set a = {a, a + D, a + 2D}, B = {a, AQ, aq2}, where a, D, Q ∈ R, if a = B, find the value of Q

From the mutual anisotropy of elements, we can see that: D ≠ 0, Q ≠± 1, a ≠ 0, and a = b.. A + D = AQA + 2D = aq2 1 or a + D = aq2a + 2D = AQ 2. From the solution of equation group 1, we can get q = 1, which should be rounded off; from the solution of equation group 2, we can get q = 1 (which should be rounded off) or - 12

One times one equals one

Invariable

A parallelogram has a base of 1.5cm and a height of 4 / 5 of the base. What is the area of the parallelogram in square centimeter?

Height = 1.5 × 4 / 5 = 1.2 cm
therefore
Area = 1.5 × 1.2 = 1.8 square centimeter

Solution equation: x + 12% x = [(1 + 40%)] y urgent!

x+12%x=[(1+40%)]y
1.12X=1.4Y
X/Y=1.4/1.12=5/4

Find the tangent equation and normal equation of the curve {y = 4T & # 178; X = 1 + 2t-t & # 178; at the point (1,16)

1 + 2t-t & # 178; = 1 → t = 0 or 2;
4T & # 178; = 16 → t = 2 or - 2
∴t＝2.
k＝dy/dx＝8t/(2-2t)＝4t/(1-t)＝4×2/(1-2)＝-8.
So the tangent is Y-16 = - 8 (x-1) → 8x + y-24 = 0;
The normal equation Y-16 = (1 / 8) (x-1) → x-8y + 127 = 0

How to solve x-3 / 7X = 12

Hello, LAN Xinlu!
x-3/7x=12
7x^2-3=84x
7x^2-84x-3=0
△=84^2-4×7×（-3）
=7056+84
=7140
x=（84±√7140）/14=（42±√1785）/7

x. If y and Z are real numbers and X-Y + 2Z = 0, then the maximum value of XZ / y square is?
If a is greater than 0, y is greater than 0, and a + B = 1, then the minimum value of AB + 1 / AB is?

Y = x + 2Z XZ / y squared = XZ (x + 2Z) squared expansion, that is, XZ (x squared + 4XZ + 4Z squared) numerator denominator divided by XZ denominator becomes mean inequality. The answer is one eighth
In the second problem, replace 1 in the numerator with a + B, and then divide the numerator and denominator by ab with the mean inequality similar to the first problem