Factorization 2x ^ 2 + 3x-2 (a-b) ^ 2 + 2 (a-b) - 3 2x ^ 3-x ^ 2-15x 3A ^ 4-8a ^ 2-16

Factorization 2x ^ 2 + 3x-2 (a-b) ^ 2 + 2 (a-b) - 3 2x ^ 3-x ^ 2-15x 3A ^ 4-8a ^ 2-16


2x^2+3x-2 =(2x-1)(x+2)
(a-b)^2+2(a-b)-3 =(a-b+3)(a-b-1)
2x^3-x^2-15x =x(2x^2-x-15)=x(2x+5)(x-3)
3a^4-8a^2-16=(3a^2+4)(a^2-4)=(3a^2+4)(a-2)(a+2)



The square minus 9 factorization of the quadratic power of X (x minus 2)


x²﹙x-2﹚²-9
=﹙x²-2x)²-9
=(x²-2x+3)(x²-2x-3)
=(x²-2x+3)(x-3)(x+1)



Can the remainder of a prime divided by 6 be 2 or 3? Why?


Impossible. If the remainder is 2 and the number is 6x + 2, then the number can be divisible by 2 and is not a prime. Similarly, 6y + 3 can be divisible by 3 and is not a prime



It is proved that the function f (x) = 1 minus 1 / X is an increasing function on (negative infinity, 0)


Just take the derivative
Derivative = 1 / x ^ 2
F (x) is monotonically increasing except at 0



We know that the function f (x) is an even function and the function on (0, + infinity) is an increasing function. Try to compare the sizes of F (- 7.5), f (- 1.5) and f (8 / 3)
&If f (2x-3) > F (x + 1) & nbsp; find the value range of X


The function f (x) is even
∴f(-7.5)=f(7.5) ,f(-1.5)=f(1.5)
And ∵ on (0, + infinity) is an increasing function, and 7.5 > 8 / 3 > 1.5
∴f(-7.5)>f(8/3)>f(-1.5)
2, ∵ is a decreasing function,
∴2x-3-3,x+1



What should be filled in the brackets!
The standard answer is no 15
First, what is prime?
Then please solve the problem and explain the reason!
Add reward points as soon as possible!


Prime numbers, or prime numbers, are natural numbers that can only be divided by one or themselves
The answer is that 13.12 can be divided by 2 and 6, 14 by 2 and 7, and 15 by 3 and 5



It is known that the probability density function of random variable x is f (x), which satisfies the condition (1), f (x) = CX, (0 ≤ x)


∫[-∞,+∞] f(x)dx=1 => ∫[0,1] cxdx=c/2=1,c=2
0,x1
Because the value range of X is [0,1]
P{1/2



The known vector M = (sin (x - π / 4), 1) vector n = (COS (x - π / 4), 3). F (x) = Mn
1) if M ‖ n, find f (x)
2) if the image of the function is shifted to the right by M (M > 0) unit length, and then down by 3 units, the function g (x) corresponding to the image is an odd function, and the minimum value of M is obtained


M / / N, then: [sin (x - π / 4)] / cos (x - π / 4) = 1 / 3, that is: Tan (x - π / 4) = 1 / 3, and: Tan (x - π / 4) = [tanx-1] / [TaNx + 1] = 1 / 3, then: TaNx = 2F (x) = sin (x - π / 4) cos (x - π / 4) + 3 = (1 / 2) sin (2x - π / 2) + 3 = - (1 / 2) cos2x + 3tanx = 2F (x) = - (1 / 2)



What is the relationship between 12 and 36? What is the greatest common factor


Multiple relation (12,36) = 12



Define a new operation "⊙", for any rational number a, B have a ⊙ B = AB-A ^ 2 + 2B, calculate (1 ⊙ 2) ⊙ (negative one and half) = ()


1⊙2=1*2-1^2+2*2=5
5 ⊙ (- 3 / 2) = 5 * (- 3 / 2) - 5 ^ 2 + 2 * (- 3 / 2) = - 35.5 = negative 35 and half