Factorization: x ^ 2-7 / 12x + 1 / 12

Factorization: x ^ 2-7 / 12x + 1 / 12

x^2-7/12x+1/12
=(x-1/3)(x-1/4)

Factorization x ^ 2 + 12x + 32

Original formula = (x + 4) (x + 8)

Factorization (1) 3ax2 + 6AX + 3ay2; (2) (X-2) (x-4) + 1

（1）3ax2+6axy+3ay2 =3a（x2+2xy+y2 ）=3a（x+y）2 ；（2）（x-2）（x-4）+1=x2-6x+8+1=x2-6x+9=（x-3）2．

Simple calculation of grade five in primary school
Primary school grade 5 simple calculation more and better, simple calculation to repeat the roll
Don't be so long

4.02＋5.4＋0.98
5.17－1.8－3.2
13.75－(3.75＋6.48)
3.68＋7.56－2.68
7.85＋2.34－0.85＋4.66
35.6－1.8－15.6－7.2
3.82＋2.9＋0.18＋9.1
9.6＋4.8－3.6
7.14－0.53－2.47
5.27＋2.86－0.66＋1.63
13.35－4.68＋2.65
47.8－7.45+8.8
0.398+0.36+3.64
15.75+3.59－0.59+14.25
42.5－(6.07＋1.13)
73.8－1.64－13.8－5.36
66.86－8.66－1.34
0.25×16.2×4
3.72×3.5＋6.28×3.5
36.8－3.9－6.1 2
5.48－(9.4－0.52)
4.8×7.8＋78×0.52
3.6×102
6.4×0.25＋3.6÷4
32＋4.9－0.9
4.8－4.8×0.5
(1.25－0.125)×8
4.8×100.1
56.5×9.9＋56.5
7.09×10.8－0.8×7.09
4.2÷3.5
320÷1.25÷8
18.76×9.9＋18.76
3.52÷2.5÷0.4
4.78÷0.2＋3.44
3.9－4.1＋6.1－5.9
0.49÷1.4
1.25×2.5×32
3.6－0.6×2
3.65×10.1
3.6－3.6×0.8
15.2÷0.25÷4
5.6÷3.5
9.6÷0.8÷0.4
4.2×99＋4.2
0.89×100.1
146.5－(23＋46.5)
17.8÷(1.78×4)
5.83×2＋4.27
(45.9－32.7)÷8÷0.125
9.7×99＋9.7
4.36×12.5×8
15.6×13.1－15.6－15.6×2.1
0.65×101
27.5×3.7－7.5×3.7
8.54÷2.5÷0.4
3.83×4.56＋3.83×5.44

If the system of equations x ^ 2 + y ^ 2 = 16 and X-Y = k with X and y as unknowns has a real solution, the value range of K is obtained
There should be a process. Write it clearly,

x-y=k
x=k+y
Substitute this formula into x ^ 2 + y ^ 2 = 16
(y+k)^2+y^2=16
turn
y^2-ky-8=0
a=1 b=k c=-8
So △ = (k) ^ 2-4 * 1 * (- 8)
=k^2+32
Because there are real solutions
So K ^ 2 + 32 > = 0

First grade mathematical oral arithmetic exercises

2+5=7
4+4=8
5+6=11
8+9=17
11+22=33
25+25=50
88+11=99
50+50=100

There is a square flower garden, the side length of the flower garden is increased by 2 meters, so the area is increased by 32 square meters. How many square meters is the original square area?

The original square side length = (32-2x2) △ 2 △ 2 = 7
Original square area = 7 & # 178; = 49 square meters

The period of a spring oscillator in harmonic motion is t
A. If the displacements of the oscillator at time t and (T + △ T) are equal in magnitude and direction, then △ t must be an integral multiple of T;
B. If the velocity of the oscillator at time t and (T + △ T) is equal and opposite;
C. If △ t = t, the acceleration of the oscillator must be equal at t and (T + △ T);
D. If △ t = t / 2, the length of spring must be equal at t and (T + △ T)

Draw the vibration image, such as sine image, when t = t / 4, the spring is at the maximum length (positive maximum displacement), after t / 2, the spring is at the source of negative maximum displacement, which is obviously not equal, and the length difference is two amplitudes (a)
I see

Cut a cuboid 2 cm along its length to get a cube whose surface area is 80 square cm less than the original cuboid. Find out the cuboid's volume

The width of the reduced surface (the edge length of the remaining cube) is 80 △ 4 △ 2 = 10 (CM). The height of the original cuboid is 10 + 2 = 12 (CM). The volume of the original cuboid is 10 × 10 × 12 = 1200 (cm3). A: the volume of the original cuboid is 1200 cm3

Is the pulse as fast as the heartbeat?

1. In general, the heart rate and pulse of healthy people are the same, because the pulse is the arterial pulse caused by cardiac ejection
2. It can be different when arrhythmia occurs, such as atrial fibrillation (heart rate 140-200, pulse is much slower, which is also one of the diagnostic criteria of atrial fibrillation), other arrhythmias can also lead to the difference between the two