Factorization of X4 + 2x3 + x2 + 1 + 2 (x + x2)

Factorization of X4 + 2x3 + x2 + 1 + 2 (x + x2)


x4+2x3+x2+1+2(x+x2)
=(x2+x)^2+2(x2+x)+1
=(x2+x+1)^2



Factorization of x4-2 (A2 + B2) x2 + (A2-B2) 2


This is the x ^ 4-2 (a \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\- 2Ab) (x-178; - a-178; - b-178



Given that the coordinates of the three vertices of the triangle ABC are a (2,3,1), B (4,1, - 2) and C (6,3,7), the multiplicity of the triangle ABC is determined
The center coordinates are,


I seem to be able to help you, but your coordinates don't understand



If the real number T satisfies f (T) = - t, then t is said to be a sub fixed point of function f (x). Let f (x) = INX and G (x) = e ^ x (where e is the sum of logarithm of natural number)
Then a m is less than 0, B M = 0, C 0 is less than m, D M is more than 1


Choose B
This problem is best illustrated
F (T) = - t, as f (x) = y = - x, that is a straight line with coefficient - 1
F (x) = INX, where x > 0, in the coordinate system, f (x) = INX and f (x) = y = - x intersect at the fourth phase limit point a (a, - b)
G (x) = e ^ x, where g (x) > 0, G (x) = e ^ X and f (x) = y = - x intersect at the second phase limit point B (- A, b)
Because point a and point B are symmetric about the origin,
There is only one fixed point, so m = B-B = 0



How to add and subtract fractions?


First, get the least common multiple of the denominator, then convert the two fractions into fractions with the least common multiple as the denominator at the same time, and then add the molecules, and then see if there is a minimum common divisor between the molecules and the denominator. After simplification, it is the result



For the equation sin3x = sin2x + SiNx, the correct one in the following statement is ()
A. For any x ∈ R, the equality holds B. for any x ∈ R, the equality does not hold C. There are infinitely many x ∈ r such that the equality holds D. the equality holds only for a finite number of X ∈ R


∵ sin3x = sin2x · cosx + cos2x · SiNx, to make sin3x = sin2x + SiNx hold, we only need cosx = cos2x = 1, that is, x = 2K π, K ∈ Z, so there are infinitely many x ∈ r to make the equation hold, so we choose C



How to teach kindergarten children's mathematics well


It's very important to cultivate children's sense of number! Guide children from physical to digital, such as: three apples can be expressed as 3



It is known that the solutions of the equations ax by = 4, ax + by = 2 are the same as those of the equations 2x + 3Y = 4, 4x + 5Y = 6, and the values of a and B are obtained


The solution of the equations 2x + 3Y = 4,4x + 5Y = 6
x=-1,y=2
Substituting x = - 1, y = 2 into the equations ax by = 4, ax + by = 2
-a-2b=4,-a+2b=2
The solution is as follows
a=-3,b=-1/2



Please fill in nine numbers from 1 to 9 in the three formulas. No repetition is allowed! () + () = () - () = () * () = ()


(4)+(5)=(9) (8)-(7)=(1) (2)*(3)=(6)



After translating the line l y = - 2x along the y-axis, we can get the line y = KX + B passing through the point (- 1,4) and the intersection of X, Y-axis and a, B (1) to find the value of a, B (2) to find the area of △ AOB
Such as the title


(1)
The slope of the line remains unchanged after translation
So k = - 2
Because it's too much (- 1,4)
So 4 = - 2 * (- 1) + B
So B = 2
So y = - 2x + 2
Let x = 0 be y = 2
Let y = 0 be x = 1
So a (1,0), B (0,2)
(2) The area of △ AOB is s = (1 / 2) * 1 * 2 = 1