If the fourth power of (x + 2) is 16, then x + 1 =? Urgent

If the fourth power of (x + 2) is 16, then x + 1 =? Urgent

x+2=2 x=0 so x+1=1

1. A quartic power B quartic power - 81
2. - A + 2A & #178; - a cubic

A quartic power B quartic power - 81
=（a²b²+9）（a²b²-9）
=（a²b²+9）（ab+3）（ab-3）
-A + 2A & #178; - a cubic
=-a（a²-2a+1）
=-a（a-1）²

Let u = {2,4,1-a}, a = {2,a2-a + 2}, if CUA = {- 1}, find the value of real number a

Because CUA = {- 1}, so - 1 = 1-A, when a = 2A = 2, a2-a + 2 = 4 satisfies CUA = {- 1}

9 / 11-1 / 3 =?

2 out of 15 + 3 out of 10
=4/30+9/30
=13/30
9 / 11-1 / 3
=27/33-11/33
=16/33

Given a circle a: (x + 3) ² + Y & #178; = 100, a certain point B (3,0) in circle a, and a circle P passing through point B and being tangent to circle a, then the trajectory equation of the center P is?
For the specific process, thank you!

Let the radius of p be r
A radius is 10
Introversion
PA=10-r
And Pb = R
So PA + Pb = 10
So it's an ellipse
2a=10
a=5
A(-3,0),B(3,0)
This is the focus
So C = 3
Then B = 4
x²/25+y²/16=1

One in 20 divided by one in 30

1/20÷1/30
=1/20×30
=3/2

1,2,4,3,6,9,（）,（）

The key to solving the number sequence problem is to find the rule. At the beginning, I separated 1,2,4 and 3,6,9, but I couldn't find any rule. But when I divided 1,2,4 and 3,6,9 into three parts, the rule came out immediately: first, 1 has one, then 2 has two: 2,2 * 2 = 4, then 3 has three, respectively 3,3 * 2 = 6,3 * 3 = 9, which is the rule. Then it should be 4, Corresponding to four numbers, they are: 4,4 * 2 = 8,4 * 3 = 12,4 * 4 = 16, and so on, so the numbers in brackets should be 4,8

63 × 73-63 × 63, simple operation

63x73-63x63
=63x(73-63)
=63x10
=630

Given that x = 2, the value of the algebraic formula - ax ^ 3 - [7 - (BX + 2aX ^ 3)] is 5. Find the value of this algebraic formula when x = - 2

When x = 2, the value of the algebraic formula - ax ^ 3 - [7 - (BX + 2aX ^ 3)] is 5, →
-a*2^3-[7-(b*2+2a*2^3)]=5→
-a*2^3+(b*2+2a*2^3)]=12
When x = - 2, the value of this algebraic expression is:
-a*(-2)^3-[7-(b*(-2)+2a*(-2)^3)]=
-{-a*2^3+(b*2+2a*2^3)]-7=-12-7=-19

What is the sum of 4 / 5 minus 1 / 5 plus 1 / 3 plus 0.375?

4/5-(1/5+1/3)+0.375
=4/5-1/5-1/3+3/8
=3/5-1/3+3/8
=(72-40+45)/120
=77/120