What is the maximum value of log 1 / 9 of 3 to the logarithm power of X + 1 / x? Find the maximum value of 3log1 / 9 (x + 1 / x) (x ＞ 0)? Note: 3 and the following are not product relations but power relations

What is the maximum value of log 1 / 9 of 3 to the logarithm power of X + 1 / x? Find the maximum value of 3log1 / 9 (x + 1 / x) (x ＞ 0)? Note: 3 and the following are not product relations but power relations

Index = LG (x + 1 / x) / LG1 / 9
=lg(x+1/x)/(-2lg3)
=lg(x+1/x)^(-1/2)/lg3
=log3[(x+1/x)^(-1/2)]
So the original formula = (x + 1 / x) ^ (- 1 / 2) = 1 / √ (x + 1 / x)
x>0
x+1/x>=2√x*1/x=2
So √ (x + 1 / x) > = √ 2
0

What is the result of comparing the power of 0.7 to the sixth and log0.76?

Log0.760, so log0.76

If the height of a cuboid is increased by 3 cm, it becomes a cube, and the surface area is increased by 60 square cm. Find the surface area and volume of the original cuboid
Product

Utilization: side area = perimeter of bottom surface × height
The increase of surface area is the side area after the increase of height
Perimeter of bottom surface: 60 △ 3 = 20cm
Side length of bottom surface: 20 △ 4 = 5cm
Original height: 5-3 = 2cm
Original surface area: 20 × 2 + 5 × 5 × 2 = 90 square centimeter
Original volume: 5 × 5 × 2 = 50 cubic centimeter

20% of a number plus 56 is equal to itself. What is the number

56÷﹙1－20％﹚＝70.

A set of even numbers that can divide 111?
Explain how to divide and be divided. Is the integer numerator or denominator

If the quotient is an integer and there is no remainder, it is called that the number a can be divided by the number B, or that the number B can divide the number A. for example, 6 △ 2 = 3, if the quotient is an integer and there is no remainder, it is called that 6 can be divided by 2, or that 2 can be divided by 6. Since quotient is an integer, it can be regarded as a fraction with denominator 1

2 / 5-1 / 7 = 3 divided by 5% = 3 / 10 + 2 / 5-1 / 2 = 1 / 4x15 divided by 1 / 4 = 5396 divided by
2 / 5-1 / 7 =
3 divided by 5% =
3 / 10 + 2 / 5 - 1 / 2 =
1 / 4x15 divided by 1 / 4 =
5396 divided by 59 = (estimated)

9/35

(square of 0.25A, cubic of B-1 / 2a, cubic of B-1 / 6A) / (- square of 0.5A)

(square of 0.25A, cubic of B-1 / 2a, cubic of B-1 / 6A) / (- square of 0.5A)
=-0.5+ab+1/3a²b²

There are ten numbers from 0 to 9. The sum of six numbers is equal to the sum of the other four numbers

No solution
1+2+3...+9=45
The sum of six numbers and four numbers is 45
And because the sum of six numbers equals the sum of four numbers equals half of the sum of ten numbers
So there is no solution

2x-y + 3Z = 3 3x + y-2z = - 1 x + y + Z = 5

2x-y+3z=3…… (1)
3x+y-2z=-1…… (2)
x+y+z=5…… (3)
Eliminate the equations of X, y and Z
From (3) × 2 - (1), 3y-z = 7
From (3) × 3 - (2), 2Y + 5Z = 16
The solution is y = 3, z = 2
Substituting: x = 0
x=0
y=3
z=2

18÷7/9+0.65×8/13-2/7×18+5/13×0.65
It should be simple

18*9/7+13/20*8/13-2/7*18+5/13*13/20
=18*9/7-2/7*18+13/20*8/13+5/13*13/20
=18*（9/7-2/7）+8/20+5/20
=18+13/20
=18 and 13 / 20