Compare the power of 6 to the power of 300, 5 to the power of 400, 4 to the power of 500

Compare the power of 6 to the power of 300, 5 to the power of 400, 4 to the power of 500

6 to the 300th power = 216 ^ 100
5 to the 400th power = 625 ^ 100
500 power of 4 = 1024 ^ 100
The maximum power of 4 is 500

Compare the negative 0.3 power of size 0.4, the negative 0.3 power of size 2, log (2) 0.8

0.4^-0.3>1
0

Factorization (12 21:33:25)
A construction site needs to cast three ring reinforcement rings with radius of 0.24M, 0.37M and 0.39m respectively. How much reinforcement do you need?

Considering that it is junior high school mathematics, this problem should start students to think about how to simplify the formula
ab+ac=a(b+c)
This problem is to find the sum of the circumference of three circles
analysis,
First, the perimeter formula is π D
(π, PI, 3.14. D, diameter. R, radius if there is no requirement. Because d = 2R, the circumference is calculated as 2 π R)
The perimeter of 0.24M ring is 2 π * 0.24M, 0.37M ring is 2 π * 0.37M, and 0.39m ring is 2 π * 0.39m
Secondly, it requires the sum of three girths
2π*0.24+2π*0.37+2π*0.39
We can see that in this formula, each term added is multiplied by a constant 2 π. Each term has to be multiplied once. If it is 10 or 100 terms, it's not too much trouble. Do you think so
If he uses his brain, he will think of the common factor AB + AC = a (B + C) and 2 π that he has learned. Here is a in the formula, which can be extracted to simplify the formula
2π(0.24+0.37+0.39)
Look, is Jane short of calculation~
If π is 3.14, 0.24 + 0.37 + 0.39 is exactly equal to 1
Is it 2 * 3.14 * 1 = 6.28m~
Hi, it's so easy to solve without a calculator~

In the triangle ABC, the line of high BD and CE intersects at point O. if the triangle ABC is not a right triangle and the angle a = 50 degrees, then the angle BOC = 50 degrees
Why are there three answers? Let's talk about two

The answer to this question should be two
(1) When ABC is an acute triangle:
The high BD and CE are in the triangle, ∠ AEO + ∠ ADB = 90 + 90 = 180 °, then ∠ EOD + ∠ a = 180 °
Therefore, ∠ BOC = ∠ EOD = 180 ° - ead = 130 °;
(2) When the triangle ABC is an obtuse triangle, we can get: ∠ BOC = ∠ a = 50 °

1/8+1/24+1/48+1/80+.+1/360 =

Please check your title
1/2×4+1/4×6+1/6×8+…… +1/18×20
=(1/2-1/4+1/4-1/6+1/6-1/8+…… +1/18-1/20)/2
=9/40

First, change the following determinant into upper triangle determinant, and find its value: the first line 1234, the second line 2341, the third line 3412, the fourth line 4123

1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
2 3 4 1 0 - 1 -2 -7 0 -1 -2 - 7 0 -1 -2 -7
3 4 1 2 0 - 2 -8 -10 0 0 -4 4 0 0 -4 4
4 1 2 3 0 -7 -10 -13 0 0 4 36 0 0 0 40
The value of the final determinant is
D=1×(-1)×(-4)×40 = 160.

3 divided by 1 / 3 - 1 / 3 divided by 3 =? Process and answer
3 divided by 1 / 3 - 1 / 3 divided by 3 =? Process and answer

3/(1/3)-(1/3)/3=3*3-(1/3)*(1/3)=9-1/9=80/9
/Is division sign, in brackets is fraction

The known proposition p: if there is a x0 belonging to R, such that x0 ^ 2 + 2x0 = 3, then not p is

Non P: for any x ∈ R, X & # 178; + 2x ≠ 3

How to calculate 4.05 minus 2.8 minus 0.7

The first use of 2.8 + 0.7 = 3.5, and then 4.05-3.5 = 0.554.05 - (2.8 + 0.7) = 4.5-4.5 - (2.8 + 0.7 = 4.5-2.8-0.7 how to calculate 4.05-2.8-0.7-7 = 4.5-2.8-0.7 = 3.5, and then 4.05-3.5 = 4.5-3.5-3.5 = 4.554.554.05-4.05 - (2.8 + 8 + 0.8 + 0.8 + 0.7 = 4.5-5-4.5-5-4.5-4.5-4.5-4.5-4.5-4.5-4.5-5-4.5-5-4.5-5-4.5-4.5-4.5-5-5-4.5-5-5-4.5-5-5-05 - (2.8 + 0.7) = 4.05-3.5 = 0.55

Given x + 4Y = 6Z, 3x-4y + 2Z = 0, find the value of 2x + 3Y / Z

The sum of X + 4Y = 6Z, 3x-4y + 2Z = 0
4x=4z,x=z
X + 4Y = 6Z, so x = 6z-4y = 6x-4y
y=5x/4
(2x+3y)/z=(2x+15x/4)/x=23/4