Zero point theorem and intermediate value theorem

Zero point theorem and intermediate value theorem


Zero point theorem and intermediate value theorem
As long as it is a continuous function, the problem becomes clear. The continuity lies in the correspondence between an X and a y value
"Zero point" and "medium" both refer to a point on the function domain [X-axis], and the corresponding function value is 0 or a special value. This corresponding point on the x-axis is also called root in some cases
If f (x) = C, finding the intermediate value point is equivalent to finding the zero point for the function f (x) - C. that is, finding the point on the x-axis where the function = 0
In addition, the existence of "at least one" table is a problem;
"Unique" usually uses derivative method to determine the uniqueness by judging the trend of monotonicity
On this basis, when a derivative function is continuous, or an original function is second-order differentiable, then the mean value theorem can be understood as the intermediate value problem or the zero point problem of the derivative function



What is the existence theorem of zeros?


If f (x) is continuous on the interval [a, b], and f (a) f (b)



Problems of zero point theorem and intermediate value theorem
The premise of these two theorems is the closed interval gun continuous function, but why does he come to the conclusion that it is in the open interval? How about at least one point? Why do we have to emphasize the open interval and the closed interval?


The values of two endpoints have been determined, one is a, the other is B. therefore, it is impossible for these two endpoints to take a value C between a and B. for example, f (a) = 1, f (b) = 5, take a number between C = 1 and 5, for example, take 3, then the point equal to 3 may be a and B. therefore, the point equal to 3 can only be a point in the open interval (a, b)
Zero point theorem is a special case of intermediate value theorem



The function y = MX2 + x-2m (M is a constant), and the intersection of the image and X-axis has the following properties______ One


When m = 0, y = x, the intersection of image and X-axis has one



Product rule in Calculus
As shown in the picture


The first is the limit multiplication algorithm, and your expression is problematic. The first condition is that the limit of two functions exists. The second is the derivation (multiplication) algorithm. The derivation formula is derived from the limit, and the result is different. There is a derivation process in the book, you can have a look, and hope it can help you!



Two teachers of a school took several students to travel and contacted two tourism companies with the same price. After negotiation, the preferential condition of company a was that one teacher should pay the full price
Two teachers of a school took some students to travel and contacted two travel companies with the same price. After negotiation, company a offered a discount
The condition is that one teacher will be charged in full, and the rest will be charged at a discount of 7.5%. The preferential condition of company B is that all teachers and students will be charged at a discount of 8%
When the number of students exceeds, the other 7.5% discount; a travel company is more preferential than B travel company. 2) after accounting, the preferential price of a travel company is 1 / 32 cheaper than B company. How many students are there?
Linear equation of one variable





The process of finding the limit solution of LIM (x → 0) xcotx


&Thank you. I don't know



In the sequence an, if A1 = 1 and 1 / a (n + 1) is the second power of the base - 1 / A and N is the second power of the base = 4, then an=


1/a(n+1)^2-1/an^2=4
So {1 / an ^ 2} is equal difference
1/an^2=1/a1^2+4(n-1)=4n-3
an^2=1/(4n-3)
an=±√[1/(4n-3)],n∈N*



No, I don't know how to say it in English


Sorry,I don't know.



The square area is about 440000 square meters. How accurate is this approximation


Individual position