Differential of composite function Known F[w*(1+t)]=K(w) Differential equation on both sides Why do you get it F'(dw + w*dt)=K' dw

Differential of composite function Known F[w*(1+t)]=K(w) Differential equation on both sides Why do you get it F'(dw + w*dt)=K' dw


In books or other people's articles?
I can only say that it's not good to write like this, especially in F '
It should be written clearly and not omitted at will
F'(w(1+t)) * (dw+w*dt) = K'(w) dw
Is that ok



Differentiation of compound function
Y = sin (2x + 1), find dy y = sin u, u = 2x + 1, according to the formula, Dy = f '(U) g' (x) DX, the result is, 2cos (2x + 1) DX if you use the formula dy = f '(U) Du: dy = D (sinu) = cos u Du = cos (2x + 1) d (2x + 1) = cos (2x + 1) 2DX = 2cos (2x + 1) DX, how can cos (2x + 1) 2DX be obtained after the second equal sign? Cos (2x + 1) d (2x + 1) = cos (2x + 1) 2xD + cos (2x + 1) d is not it? Why is it equal to cos (2x + 1) 2DX? Where is the following? (q.q)


First of all, you need to understand that D is a differential operator, which has indicated a kind of operation. The meaning of COS (2x + 1) d (2x + 1) is the differential of COS (2x + 1) multiplied by 2x + 1 to x, not the differential of COS (2x + 1) d (2x + 1). If you calculate the differential as a whole, the mistake is here, This is the simplest differential, and then add the preceding one, cos (2x + 1) 2DX



The ratio of the three numbers of a, B and C is 1:2:3. If the average is 30, what are the numbers of a, B and C?


30×3÷(1+2+3)=15
A: 15 × 1 = 15
B: 15 × 2 = 30
C: 15 × 3 = 45



Given that the sum of the two sides of a right triangle is 2, what is the maximum area of the triangle?


The maximum area is 1 / 2 when both sides are 1
Let two sides be a and B respectively
A + B = 2, find the maximum value of AB / 2
Because B = 2-A, then AB / 2 = a (2-A) / 2 = - (A & # 178; - 2A) / 2 = - (A-1) &# 178 / 2 + 1 / 2
The maximum area is 1 / 2 when a = 1



The average number of a, B and C is 120. The average number of B and C is 90. What's the number of a
You don't have to have an answer


The sum of numbers a, B and C is 120 times 3 = 360
The sum of the two numbers is 90 times 2 = 180
A, B, C - B, C = 360-180 = 180
So the number a is 180



Let AX = B have solutions α 1 = (1,2,3), α 2 = (- 1,2,3), and R (a) = 2, then the general solution of AX = B is________ .
Let AX = B have solutions, α 1 = (1,2,3) ^ t, α 2 = (- 1,2,3) ^ t, and R (a) = 2, then the general solution of AX = B is________ .


A1-a2 is a fundamental solution
So the general solution is K (A1 - A2) + A1



Party A and Party B process 1500 parts respectively. Because Party B adopts new technology, the number of parts processed by Party B is three times that of Party A at the same time. Therefore, Party B processes less than 20 hours than Party A. how many parts do they process each hour?


Let a process x per hour, then B process 3x per hour. According to the meaning of the problem, 1500x = 15003x + 20, the solution is x = 50. Test: when x = 50, 3x = 3 × 50 ≠ 0, so x = 50 is the root of the original fractional equation, and conforms to the meaning of the problem. Answer: a processes 50 per hour, B processes 150 per hour



7x+5(20-x)=180


7x+5(20-x)=180
7x+100-5x=180
2x+100=180
2x=180-100
2x=80
x=40
Inspection:
7x + 5 (20-x) = 7 times 40 + 5 times 20 minus 40 = 280 + 5 times 20-5 times 40 = 280 + 100-200 = 380-200 = 180
The left equals 180, and the right equals 180
So x = 40
See?
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There are 14 million kg grain in the three warehouses. The grain quality ratio of warehouse A and warehouse B is 3:4, and that of warehouse B and warehouse C is 6:7
There are 14 million kilograms of grain in the three warehouses. The grain quality ratio of warehouse A and warehouse B is 3:4, and the grain quality ratio of warehouse B and warehouse C is 6:7. Each of the three warehouses has 10000 kilograms less grain? One parent's help,


A: B: C = 9:12:14
1400÷(9+12+14)=40
A = 9 × 40 = 3.6 million kg
B = 12 × 40 = 4.8 million kg
C = 14 × 40 = 5.6 million kg



The sum of three fourths of a number plus five is equal to the difference of two times of it minus nine. Let a number be x, and the equation is []


3/4X+5=2X-9
14=5/4X
X=56/5